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Answer 1

GIVEN QUESTION -

Find the lateral surface area of the cuboids whose dimensions are :

i) Length = 24 cm, breadth = 25 cm and height = 6cm

ii) Length = 16 m, breadth = 25 cm and height = 4m

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$☯ \: \sf Let's \: understand \: the \: question \: first \: -$

In this question the dimensions of the cube is given and we need to find the lateral surface area .

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1 )

$\begin{gathered}\sf Given \: that \begin{cases} & \sf{Length = \bf{24 \: cm}} \\ & \sf{Breadth= \bf{25 \: cm}} \\ & \sf{Height =\bf{26 \: cm}} \end{cases}\\ \\\end{gathered}$

$\begin{gathered}\sf To \: find \begin{cases} & \sf{Lateral \: surface \: area} \end{cases}\\ \\\end{gathered}$

$\begin{gathered}\sf Solution \begin{cases} & \sf{Lateral \: surface \: area= \bf{588 \: cm ^{2} }} \end{cases}\\ \\\end{gathered}$

$\begin{gathered}\sf Formula \: used \begin{cases} & \sf{Lateral \: SA \: of \: cubiod = \bf{2h(l + b)}} \end{cases}\\ \\\end{gathered}$

Let's solve it step by step -

lateral SA of cuboid = 2h ( l + b )

$\longrightarrow \tt 2 \times 6 \: (24 + 25)cm ^{2}$

$\longrightarrow \tt 12 \: (49)cm ^{2}$

$\Longrightarrow \tt 588cm ^{2}$

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2)

$\begin{gathered}\sf Given \: that \begin{cases} & \sf{Length = \bf{16 \: m}} \\ & \sf{Breadth= \bf{25 \: cm}} \\ & \sf{Height =\bf{4 \: m}} \end{cases}\\ \\\end{gathered}$

$\begin{gathered}\sf To \: find \begin{cases} & \sf{Lateral \: surface \: area} \end{cases}\\ \\\end{gathered}$

$\begin{gathered}\sf Solution \begin{cases} & \sf{Lateral \: surface \: area= \bf{328\: cm ^{2} }} \end{cases}\\ \\\end{gathered}$

$\begin{gathered}\sf Formula \: used \begin{cases} & \sf{Lateral \: SA \: of \: cubiod = \bf{2h(l + b)}} \end{cases}\\ \\\end{gathered}$

Let's solve it step by step -

lateral SA of cuboid = 2h ( l + b )

$\longrightarrow \tt 2 \times 4 \: (16 + 25)cm ^{2}$

$\longrightarrow \tt 8\: (41)cm ^{2}$

$\Longrightarrow \tt 328cm ^{2}$

Answer 2

Question:-

Find the lateral surface area of the cuboids whose dimensions are:-

i) Length = 24 cm, breadth = 25 cm and height = 6cm

ii) Length = 16m, breadth = 25 cm and height = 4m

Required Solutions:-

i) Given:-

• Length = 24cm
• Breadth = 25 cm
• Height = 6cm

To Find:-

• Lateral Surface Area

Solution:-

We know,

Formula for lateral surface area of a cuboid is:-

$\sf{2(Length + Breadth)\times height}$

Hence,

$\sf{LSA = 2(24 + 25)\times 6}$

$\sf{LSA = 2\times 49\times 6}$

$\sf{LSA = 588\:cm^2}$

Hence, The Lateral Surface Area of the cuboid is 588 cm².

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ii) Given:-

• Length = 16m
• Breadth = 25cm
• Height = 4m

To Find:-

• Lateral Surface Area

Solution:-

Here we can se that the units of the dimensions are different. Hence we need to make all the units equal. We will convert all the units into m

Length is already in metre units.

Breadth is in cm units. Hence we need to convert it into metre by dividing the value by 100

Breadth = 25 cm = $\sf{\dfrac{25}{100}}$ = 0.25 m

Height is also in metre units.

Hence, now we can find the lateral surface area.

$\sf{LSA = 2(16 + 0.25)\times 4}$

$\sf{LSA = 2\times 16.25\times 4}$

$\sf{LSA = 130\:m^2}$

Hence the Lateral Surface Area of the cuboid is 130 m².

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Other formulas related to cuboid:-

• Volume = Length × Breadth × Height cu.units

• Total Surface Area = 2(LB + BH + HL) sq.units

• Here L = Length, B = Breadth and H = Height.

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