Plz answer it questions no. 10
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1. As the key K is Opened, so, there is no Potential Difference across ADB circuit and consequently no current flowing through the circuit.
Equivalent Resistance,R = 4+4= 8 ohms.
Current in ACB, I = V/R = 12/8 = 3/2 = 1.5 Amperes.
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2. R1 and R2 are in Series...
R12 = 4 + 4 = 8 ohms
R3 and R4 are in Parallel....
R34 = (4*4)/(4+4) = 2 ohms
Total Resistance, R = 8 + 2 = 10 ohms
As, I = V/R
=> I = 12/10 = 1.2 A
Therefore, I = 1.2 A
So, the current is 1.2 Amperes.
Equivalent Resistance,R = 4+4= 8 ohms.
Current in ACB, I = V/R = 12/8 = 3/2 = 1.5 Amperes.
=================================
2. R1 and R2 are in Series...
R12 = 4 + 4 = 8 ohms
R3 and R4 are in Parallel....
R34 = (4*4)/(4+4) = 2 ohms
Total Resistance, R = 8 + 2 = 10 ohms
As, I = V/R
=> I = 12/10 = 1.2 A
Therefore, I = 1.2 A
So, the current is 1.2 Amperes.
Gatha3:
Thanks
But why in ADB there would not be any potential difference
bcoz key is present in ABD.
Moreover, ACB and ADB are connected in parallel...
so if we open the key and break the circuit of ADB then also it will not affect ACB because it is connected in parallel and gets the same amount of voltage..
i hope you got it !
:-)
Thanks
Answered by
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when key is open
no current flow through the part ADB
therefore,resistance=R1+R2
=4+4 = 8 ohms
by ohms law
v=ir
12=i×8
I=1.5 ohms
when key is closed
current flow through the part ADB
therefore,1/resistance=1/R1+1/R2
1/resistance=1/4+1/4=1/2 ohms
overall resistance=resistance 1 + resistance 2
=2+2=4 ohms
by ohms law
v=ir
12=i×4
I=3 ohms
please mark me as brainliest
Thanks
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