Question

plz answer it's urgent.... if alpha and beta are the zeros of polynomial 6 Y ^2-7 y+2 find a quadratic polynomial whose zeros are 1/Alpha +1/beta

Answer 1

Hey user



Here is your answer




$given \: equation \: = 6 {y}^{2} - 7y + 2 \\ \\ \\ comparing \: the \: equation \: with \: standard \: form \\ \\ \\ here \: a \: = 6 \: \: \: \: \: \: b = - 7 \: \: \: \: \: \: c = 2 \\ \\ \\ \alpha \: and \: \beta \: are \: the \: roots \: of \: equation \: \\ \\ \\ \alpha + \beta = \frac{ - b}{a} \\ \\ \\ = \frac{7}{6} \\ \\ \\ \alpha \beta = \frac{c}{a} \\ \\ \\ = \frac{2}{6} \\ \\ \\ \frac{1}{ \alpha } + \frac{1}{ \beta } = \frac{ \alpha + \beta }{ \alpha \beta } \\ \\ \\ = \frac{7}{6} \times \frac{6}{2} \\ \\ \\ = \frac{7}{2} \\ \\ \\ = 3.5$


thank you.