Math, asked by himanya37, 3 months ago

plz answer it step by step​

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Answered by Anonymous
34

Answer:

\underline{\underline{ \sf \huge \red{Answer :-}}}

==>> P+(Q-R)=9x²+3x-6

Step-by-step explanation:

q - r = 6 {x}^{2} + 8x -8\\ then \\ p + (q - r) = 9 {x}^{2}  + 3x -6

Answered by Arpit000001
1

Answer:

p=3x^2 - 5x + 2

q=11x^2 + 3x - 1

r= 5x^2 - 5x+7

p+(q-r)=?

putting the value,

3x^2-5x+2+{(11x^2+3x-1)-(5x^2-5x+7)}

3x^2-5x+2+(11x^2+3x-1-5x^2+5x-7)

3x^2-5x+2+(11x^2-5x^2+3x+5x-1-7)

3x^2-5x+2+6x^2+8x-8

3x^2+6x^2-5x+8x+2-8

9x^2+3x-6 Your answer.

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