Math, asked by sagarikasharma1, 1 year ago

Plz answer it...URGENT!!!

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Answered by KunalTheGreat
0
cosec A + cot A - 1 / cot A - cosec A + 1 
we know that,cosec ² A - cot ² A = 1 
substituting this in the numerator 
cosec A + cot A -(cosec ² A - cot ² A) / (cot A - cosec A + 1) 
x²-y²= (x+y)(x-y) 
cosec A + cot A - (cosec A + cot A) (cosec A - cot A) / (cot A - cosec A + 1) 
taking common 
(cosec A + cot A)(1-cosec A + cot A) / (cot A - cosec A + 1) 
cancelling like terms in numerator and denominator 
we are left with cosec A + cot A 
= 1/sin A + cos A/sin A 
= (1+cos A) / sin A
GIVE A THUMBS UP  :-

sagarikasharma1: Can u plz post it in ur own handwriting? It will be more convenient for me
KunalTheGreat: sorry im in hurry could type it only
sagarikasharma1: Still it is not providing the right proof .plz look at it again
KunalTheGreat: cosec A + cot A - 1 / cot A - cosec A + 1
we know that,cosec ² A - cot ² A = 1
substituting this in the numerator
cosec A + cot A -(cosec ² A - cot ² A) / (cot A - cosec A + 1)
x²-y²= (x+y)(x-y)
cosec A + cot A - (cosec A + cot A) (cosec A - cot A) / (cot A - cosec A + 1)
taking common
(cosec A + cot A)(1-cosec A + cot A) / (cot A - cosec A + 1)
cancelling like terms in numerator and denominator
we are left with cosec A + cot A
= 1/sin A + cos A/sin A
= (1+cos A) / sin A
KunalTheGreat: now check
sagarikasharma1: Omg its given to proof 1+cosa/1+sins
sagarikasharma1: Sins
sagarikasharma1: Sin a*
sagarikasharma1: Not 1+cosa/sina
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