Question

plz answer its urgent
⚠️don't spam⚠️​

Answer 1

Answer:

$4. \: \: \frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{3} - \sqrt{2} } = a + b \sqrt{6} \\ \\ \frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{3} - \sqrt{2} } \times \frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{3} + \sqrt{2} } = \frac{ {( \sqrt{3} + \sqrt{2} ) }^{2} }{ { \sqrt{3} }^{2} - { \sqrt{2} }^{2} } \\ \\ \frac{3 + 2 + 2 \sqrt{2} \sqrt{3} }{3 - 2} = \frac{5 + 2 \sqrt{6} }{1}$

Value of a = 5 and b = 2 ( option A. is correct )

Identities used in this answer:

• (a+b)² = a² + b² + 2ab

• (a+b) (a-b) = a² - b²

$5. \: \: \: \: \frac{7}{3 \sqrt{3} - 2 \sqrt{2} } \\ \\ rationalising \: denominator \\ \\ \frac{7}{3 \sqrt{3} - 2 \sqrt{2} } \times \frac{3 \sqrt{3} + 2 \sqrt{2} }{3 \sqrt{3} + 2 \sqrt{2} } \\ \\ = \frac{7(3 \sqrt{3} - 2 \sqrt{2} )}{ {(3 \sqrt{3}) }^{2} - {(2 \sqrt{2} )}^{2} } = \frac{{7(3 \sqrt{3} - 2 \sqrt{2} )}}{27 - 8} \\ \\ = \frac{{7(3 \sqrt{3} - 2 \sqrt{2} )}}{19}$

Option B. is correct = 19.

Identity used in this answer :

• (a+b) (a-b) = a² - b²

Answer 2

$\Large\tt{waah \:bhai!}$

mai abhi tak yaad hu aapko

$\huge\sf\it \purple{♡thank \: you \: so \: much♡}$

aur kaise ho?

everything fine?

orh life kesi chal rahi h

report it