Question

plz answer its very urgent
answer step by step​

Answer 1

Step-by-step explanation:

Q1. let angle OBC be x and angle OCB be y

A+B+C = 180

2x + 2y + A = 180

A= 180 - 2x -2y

A/2 = 90 - x - y

A/2 - 90 = -x - y ----------(1)

OBC+OCB + BOC = 180

x+y+BOC = 180

BOC = 180-x-y

BOC = 180 + A/2 -90 ----------(From 1)

Thus, Angle BOC = 90 + Angle A/2

Q2. let angle OBC be x and angle OCB be y

2x = A+C ------(1)

2y = A+B ------(2)

2x + 2y = A + A + B + C

2x + 2y = A + 180

x + y = A/2 + 90 --------(3)

OBC+ OCB + BOC = 180

x + y + BOC = 180

A/2 + 90+ BOC = 180

BOC = 180 - A/2 - 90

Thus, Angle BOC = 90 - Angle A/2

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