Question

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Answer 1

Answer:

first answer

Given, 6x2−5x−6

=6x2−9x+4x−6

=3x(2x−3)+2(2x−3)

=(3x+2)(2x−3)

2nd answer

Given : 4x2+9y2+16z2+12xy−24yz−16zx

According to the equation,

(a+b+c)2=a2+b2+c2+2ab+2bc+2ca

So we get,

Using the formula we can it arite it as

4x2+9y2+16z2+12xy−24yz−16zx=(2x)2+(3y)2+(−4z)2+2(2x)(3y)+2(3y)(−4z)+2(2x)(−4z)

On further calculation we get,

4x2+9y2+16z2+12xy−24yz−16zx=(2x+3y−4z)2

It can be written as

4x2+9y2+16z2+12xy−24yz−16zx=(2x+3y−4z)(2x+3y−4z)

Answer 2

Answer:

hope it is useful for you