plz answer me
answer aor b only one of these
Answers
a)
mass BaCl2 =12.48g
molar mass of BaCl2 =208.23
moles = mass /molar mass
moles = 12.48/208.23
moles =0.06
mass of water =1000g = 1 kg
molality
= moles of BaCl2 / mass of solvent (kg)
=0.06/1
molality = 0.06m
∆Tb = ∆T - ∆T•
∆Tb =100.0832 - 100
∆Tb = 0.0832
∆Tb = i K b × m
i = ∆ T b / k b × m
i = 0.0832/0.52×0.06
i =0.0832/0.0312
i = 2.66
BaCl2 ---> Ba 2+ + 2Cl -
total no of ions = 3 = n
a = i - 1 / n - 1
a = 2.66 - 1 / 3 - 1
a = 1.66 /2
a = 0.83
a =83%
a represents degree of dissociation
(b )
(π) osmotic pressure =6.8 atm
M = 0.15
T =310
R = 0.082 L atm K ^-1 mol ^-1
π V = i n R T
π = i n/V RT
π = i M R T
i = π / M R T
i = 6.8 / 0.15 ×0.082 × 310
i = 6.8/3.813
i = 1.78
K Cl ---> K+ + Cl-
n =2
a = i - 1/ n-1
a = 1.78 - 1/2-1
a = 0.78/1
a = 0.78
a = 78%
Answer:
a)
mass BaCl2 =12.48g
molar mass of BaCl2 =208.23
moles = mass /molar mass
moles = 12.48/208.23
moles =0.06
mass of water =1000g = 1 kg
molality
= moles of BaCl2 / mass of solvent (kg)
=0.06/1
molality = 0.06m
∆Tb = ∆T - ∆T•
∆Tb =100.0832 - 100
∆Tb = 0.0832
∆Tb = i K b × m
i = ∆ T b / k b × m
i = 0.0832/0.52×0.06
i =0.0832/0.0312
i = 2.66
BaCl2 ---> Ba 2+ + 2Cl -
total no of ions = 3 = n
a = i - 1 / n - 1
a = 2.66 - 1 / 3 - 1
a = 1.66 /2
a = 0.83
a =83%
a represents degree of dissociation
(b )
(π) osmotic pressure =6.8 atm
M = 0.15
T =310
R = 0.082 L atm K ^-1 mol ^-1
π V = i n R T
π = i n/V RT
π = i M R T
i = π / M R T
i = 6.8 / 0.15 ×0.082 × 310
i = 6.8/3.813
i = 1.78
K Cl ---> K+ + Cl-
n =2
a = i - 1/ n-1
a = 1.78 - 1/2-1
a = 0.78/1
a = 0.78
a = 78%