Question

plz answer me fast ​

Answer 1

Answer:

As the required line is parallel to the line

$2x + 3y + 7 = 0$

So ,

Equation of the line parallel to this will be of the form

$2x + 3y + k = 0$

Also ,

we have when passing point of this line so by putting the coordinates of that passing point In the equation of the line at the places of x and y respectively we can find the value of k and after putting the value of k in the above equation we can find the equation of the required line as :-

$The \: line \: passes \: through \: (5,4)\: \\ so \: it \: will \: satisfy \: the \: \: e quation \: of \: line \: \\ \implies2 \times 5 + 3 \times 4 + k = 0 \\ \implies \: k = - 22$

$So \: the \: equation \: will \: be \\ 2x + 3y - 22 = 0 \: \: \: \: \: \: \: \: \: \: \: \: \: \boxed{ \boxed{ANSWER}}$

Answer 2

the coefficient of X and Y will be same in the required equation and will satisfy the given point so

eq will be 2x+3y-22=0