Question

plz answer me fast i, ii, iii, v

Answer 1

i) 4, 7p

4*7p= 28p

ii) -4p, 7p

-4p*7p= -(28(p)^2)

iii) -4p, 7pq

-4p*7pq= -(28q(p)^2)

v) 4p, 0

4p*0= 0

Answer 2

i ) 4 × 7p = 28p
ii) -4p × 7p =
$- 28p ^{2}$
iii) -4p × 7pq =
$- 28p {}^{2} q$

v) 4p ×0 = 0