Question

plz answer me friends​

Answer 1

$let \: p(x) = {x}^{3} - 3 {x}^{2} + x + 2 \\ zero \: of(x - 2) = 2 \\ p(2) = (2) ^{3} - 3(2) ^{2} + 2 + 2 \\ = 8 - 3 \times 4 + 2 + 2 \\ = 12 - 12 \\ = 0 \\ now \\ p(x) = {x}^{3} - {3x}^{2} + x + 2 \\ zero \: of(2x + 4) = - 2 \\ p( - 2) = ( - 2)^{3} + 3( - 2) ^{2} + ( - 2) + 2 \\ = - 8 + 3 \times 4 - 2 + 2 \\ = - 8 + 12 - 2 + 2 \\ = - 10 + 14 \\ = 4$

hope it helps