Question

plz answer me .

If 100 g of calcium carbonate on heating produces 44 g of carbon dioxide , how much quicklime will be formed ? which law is followed for solving this problem?

Answer 1

Answer : 56 gram of quicklime will be formed. The Law of conservation of mass is followed for solving this problem.

Solution : Given,

The mass of calcium carbonate = 100 g

The mass of carbon dioxide = 44 g

The balanced chemical reaction is,

$CaCO_3\overset{\Delta }{\rightarrow}CaO+CO_2$

Law of conservation of mass : In a chemical reaction, the mass of products must be equal to the mass of reactants.

According to the law of conservation of mass, 100 gram of calcium carbonate will produces 100 gram of products.

The mass of calcium carbonate = 100 gram

The mass of carbon dioxide = 44 gram

Let, The mass of Quicklime = X gram

Mass of calcium carbonate = Mass of carbon dioxide + Mass of Quicklime

100 gram = 44 gram + X gram

X = 100 - 44 = 56 gram

Therefore, 56 gram of quicklime will be formed and the Law of conservation of mass is followed for solving this problem.

Answer 2

Answer:

56 g , quicklime will be formed