Math, asked by noushad89, 1 year ago

plz answer me
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Answered by sumantmodi
0

Answer:

P(A) = 6/11, P(B) = 5/11 , P(AUB) = 7/11

Step-by-step explanation:

(I)P(AUB)= P(A) + P (B) - P (A intersection B)

7/11 = 6/11 + 5/11 - P(A intersection B)

7/11 = 11/11 - P(A intersection B )

P(A intersection B) = 1 - 7/11 = 4/11

(ii) P(A/B) = P(A) - P ( A intersection B)

= 6/11 - 4/11

= 2/11

(iii) P(B/A) = P(B) - P (A intersection B)

= 5/11 - 4/11

= 1/11

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