plz answer me mate plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz
Answers
2answer).
perimeter =42
S=42\2=21cm
s-a=21-18=3cm
s-b=21-10=11cm
s-c=21-14=7cm
a=18cm
b=10cm
s=a+b+c\2
s=18+10+c\2
21=18+10+c\2
42=28+c
c=14cm
area=√s(s-a)(s-b)(s-c)
=√21×3×11×7
=√21×21×11
=21√11cm²
3answer).
12x,7x and 25x
perimeter=a+b+c
540=12x+17x+25x
540=54x
x=540\54
x=10
a=12x=12(10)=120
b=17x=17(10)=170
c=25x=25(10)=250
s=perimter\2
s=540\2
s=270cm
s-a=270-120=150
s-b=270-170=100
s-c=270-250=20
area=√s(s-a)(s-b)(s-c)
=√270×150×100×20
=√270×30×5×100×5×5
=√8100×25×400
=√90²×5²×20²
=90×5×2
=9000cm²
9answer).
s=a+b+c\2
s=13+13+10\2
s=36\2
s=18cm
area of triangle=√s(s-a)(s-b)(s-c)
=√18(18-13)(18-13)(18-10)
=√18×5×5×8
=√3×3×2×5×5×2×2×2
=√3²×2²×2²×5⅝
=3×2×2×5
=60cm²
In ∆APB using Pythagoras theorem
AB²=AP²+PB²
(13)²=AP²+(5)²
AP²=169-25
AP²=144
AP=12
10answer).
suppose AB=a=20
BC=b=21
CA=c=?
perimeter of ∆ABC=a+b+c
70=20+21+c
c=29cm
s=perimeter\2
=70\2
=35cm
area of ∆ABC=√s(s-a)(s-b)(s-c)
=√35(15)(14)(6)
=√35×15×14×6
=√7×5×5×3×7×2×3×2
=√7²×5²×3²×2²
=7×5×3×2
=35×6
=210cm²
hope it is helpful...
please mark as brainliest....
