Science, asked by kanwalgopi, 5 hours ago

plz answer me plz plz plz plz plz​

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Answered by tochigeorge13
0

Answer:

This was quite much!  IT TOOK ME SO MUCH TIME!!

I didn't do solve this I found these answers expert verified when I searched for the questions.

I really hope this helps so much!!

Explanation:

1.Given:

Initial velocity= 36km/h=36x5/18=10m/s

Final velocity =54km/h=54x5/18=15m/s

Time =10sec

Acceleration = v-u/ t

=15-10/10=5/10=1/2=0.5 m/s2

Distance =s

From second equation of motion:

S=ut +1/2×at²  (ut= initial velocity   at²= acceleration × time²)

=10*10+1/2*0.5*10*10

=100+25

=125m

So distance traveled is 125m

2.

initial velocity = 10m/s (change from km/hr to m/s)

final velocity =  15m/s

DECELERATION = (initial - final velocity) / time

time given = 10 sec

deceleration = 10 m/s - 15 m/s / 10 sec

deceleration = -5/10

RETARDATION = -0.5

3.

1) displacement = 0

      distance=22/7x20m

 2) displacement= 20m

  distance=(1.5)22/7x20

3) displacement=0

distance=(2) 22/7x20m

 4) displacement=20m

distance=(2.5) 22/7x20m

4.

Given; u=0

a=5m/s  

              t=5sec.

v=u+at

V=0+5*5

V=25 m/s.

5.Given:

Maximum speed= 90km/hr

Time=10hrs

DISTANCE = 500km

Average speed= TOTAL DISTANCE/ TOTAL time

= 500/ 10

=50km/ hr

Ratio of maximum speed and average speed is = 90/ 50

=9:5

Ratio of maximum speed and average speed is =9:5

6. As the car is starting from rest ,

Initial velocity = u = 0 m/s

Final velocity = v = 54 km/hr

To convert km/hr to m/s , we multiply it by 5/18

Final velocity = v = 54 km/hr = 54 x 5/18  = 15 m/s

Time (t) = 2 sec

a = acceleration

Equation of motion :

v = u + at

15 = 0 + 2a  (We r finding aceleration(a))

a = 15/2 = 7.5 m/s²

(i) Acceleration = 7.5 m/s²

Equation of motion :

s = distance traveled

s = ut + 1/2 at²

s = 0 + 1/2 × 7.5 × 2²

(ii) Distance Travelled = 15 metres

7.1) What is the net displacement?

Ans. Displacement for the above situation is 0. As we know, that displacement is the shortest path from the initial to the final point. Here, the initial and the final points are the same, and hence, it takes no time to travel. So, the displacement is 0.

2) What is the distance?

Ans. Distance for the above situation is 200 m. Here, the ball has to cover a distance of 100 m and while coming back, again it has to cover the same distance, hence, the distance to be covered here is 200 m.

Distance =100 + 100 = 200

 

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