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Answered by
6
Answer:
since the point lie on the line
it satisfty the line equation
then,
2x-3y-13=0
put x as a-5
y as 2a -9
2(a-5)-3(2a-9)-13=0
2a-10-6a+27-13=0
-4a-23+27=0
-4a+4=0
a=1
[ since pic is not clear, i took the line equation as 2x-3y-13=0]
if the number is different ,,then also procedure is same
Answered by
1
Step-by-step explanation:
2x-3y-13=0
put X as a–5
y as 2a–9
2(a–5)–3(2a–9)–13=0
2a–10–6a+27–13=0
–4a–23+27=0
–4a+4=0
a=1
I HOPE IT'S HELPFUL FOR YOU.....MARK AS ON BRAINLIST.....
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