Question

plz answer me question no. 9​

Answer 1

ANSWER:-

Given:

The acute angles of a right angle triangle are in the ratio 4:5.

To find:

Each angle.

Solution:

As we know that right angled triangle, one angle is 90°.

⚫Let the second angle be 4x

⚫Let the third angle be 5x

According to the question:

=) 4x + 5x + 90° = 180° [property of ∆]

=) 9x + 90° = 180°

=) 9x = 180° - 90°

=) 9x = 90°

=) x= 90/9

=) x= 10°

So,

⚫Second angle, 4x = 4× 10° = 40°

⚫Third angle, 5x = 5× 10° = 50°

Hope it helps ☺️

Answer 2

Answer:

Sum of angles of ∆ =180°

It is right angle triangle

So one angle=90°

Let the two other angles of ratio4:5 be 4x & 5x

90°+4x+5x=180°

4x+5x=180°- 90°

4x+5x=90°

9x=90°

x=90°÷9

x=10

4x=4×10=40°

5x=5×10=50°

The ACUTE ANGLES of right angled triangle in ratio4:5 are

40° and50°.

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