Question

plz answer me quick! The sum of three consecutive integers is 5 more than the smallest of the integers. find the integers. ​

Answer 1

let the first integer be 'x'

since integers are consecutive , other two integers = x+1 , x+2

Let the sum of integers be y

X + X+1 + X+2 = y

It is given that sum of integers is 5 more than frst integer.

sum of integers = x+5 = y

x + x+1 + x+2 = x+5

3x + 3 = x+5

2x = 2

x=1

smallest integer = 2

second integer = 2+1 = 3

third integer = 2+2 = 4

Integers are     2,3,4

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