Question

plz answer me the question​

Answer 1

Answer:

Given that the equation is,

2x+1/(x+a)(bx-1)=5/(x+a)-3/(bx-1)

Take LCM,

2x+1/(x+a)(bx-1)=5(bx-1)-3(x+a)/(x+a)(bx-1)

2x+1=5bx-5-3x-3a

compare X coefficients on both sides,

5b-3=2

5b=5

b=1

Now compare constants,

-3a-5=1

-3a=6

a=-2

Step-by-step explanation:

Hope it helps you frnd......