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Answer:
(x + 1)(x - 1)(x² + 1)
Step-by-step explanation:
Given polynomial are:
⇒ x³ + x² + x + 1 and x⁴ - 1
(i)
Factors of x³ + x² + x + 1
= (x³ + 1) + (x² + x)
= (x³ + 1) + x(x + 1)
We know that a³ + b³ = (a + b)(a² - ab + b²)
= (x + 1)(x² - x + 1) + x(x + 1)
= (x + 1)[x² - x + 1 ) + x]
= (x + 1)[x² - x + 1 + x]
= (x + 1)(x² + 1).
(ii)
Factors of x⁴ - 1.
= (x²)² - (1)²
We know that a² - b² = (a + b)(a - b)
= (x² + 1)(x² - 1)
= (x² + 1)(x + 1)(x - 1).
Now,
LCM of x³ + x² + x + 1 and x⁴ - 1.
⇒ (x + 1)(x² + 1)(x - 1).
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