Question

plz answer me this questions please quickly, using the method of elimination...

plz quickly.......​

Answer 1

$\huge\mathcal\blue{Solution}$

The given pair of linear equations are :-

$\frac{x}{2} + \frac{y}{3} = 8 \: \: \: .........(i)$

and

$\frac{5x}{4} - 3y = - 3 \: \: \: \: ........(ii)$

By multiplying eq . (i) with 6 and eq .(ii) with 4 we get ....

$= > \frac{x}{2} \times 6 + \frac{y}{3} \times 6 = 8 \times 6$

$= 3x + 2y = 48\: \: \: ........(iii)$

and

$= > \frac{5x}{4} \times 4 - 3y \times 4 = - 3 \times 4$

$= 5x - 12y = -12 \: \: \: .........(iv)$

Now , by multiplying 5 in eq .(iii) and 3 in eq. (iv) , we get ...

$= > 15x + 10y = 240$

and

$15x - 36y = -36$

Now by subtracting both equations ...

15x + 10y = 240

15x - 36y = -36

(-)__(-)__(-)_________

46y = 276

y = 276/46

$y= 6$

Now putting the value of y in eq.(iv)

5x - 12y = -12

=> 5x - 12 × 6 = -12

=> 5x = -12 + 72

=> 5x = 60

=> x = 12

Hence , the value of x is 12 and y is 6 .

Answer 2

Heya!

refef the attachment!