plz answer my holiday homework
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Acceleration ,a = -10m/s² (opposite direction of motion)
Final velocity ,v = 0m/s
Time taken ,t = 5s
To Find:-
Distance covered by the car before coming to rest ,s
Solution:-
⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀According to the Question
Firstly we calculate the initial velocity of the car . Using 1st equation of motion
v = u + at
where,
v is the final velocity
a is the acceleration
u is the initial velocity
t is the time taken
Substitute the value we get
:\implies:⟹ 0 = u + (-10) × 5
:\implies:⟹ -u = -50m/s
:\implies:⟹ u = 50m/s
So the initial velocity of the car is 50m/s
Now, calculating the final velocity of the car by using 3rd equation of motion.
v² = u² + 2as
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