Question

Plz Answer my question​

Answer 1

$\:\: \underline{\underline{\bf{\large\mathfrak{~~Solution 1~~}}}}$

let the three consecutive integers are (x-1),X,

(X+1)

therefore according to the problem...

$= > (x - 1) + x + (x + 1) = 66 \\ = > 3x = 66 \\ = > x = 22$

therefore the integers are ....21,22,23

$\:\: \underline{\underline{\bf{\large\mathfrak{~~Solution2~~}}}}$

let the width of the rectangular figure is =a

therefore the length=X+7

now according to the problem...

$= > 2(a + a + 7) = 66 \\ = > 2a = 33 - 7 \\ = > a = \frac{26}{2} \\ = > a = 13$

therefore the width is =13 m and length=20 m

$\:\: \underline{\underline{\bf{\huge\mathfrak{~ hope~this~help~you ~}}}}$

Answer 2

Answer:

First consecutive integer no.=21

Second consecutive integer no.=22

Third consecutive integer no.=23

Step-by-step explanation:

Let one consecutive integer will be X

Another consecutive no. will be X+1

And next consecutive no. will be X+2

Sum of these three consecutive no. will be 66

So

X,X+1,X+2

x+x+1+X+2=66

3x+3=66

3x=66-3

3x=63

x=63/3

x=21

First consecutive integer no.x=21

Second consecutive integer no. x+1=21+1=22

Third consecutive integer no. x+2= 21+2=23