Question

plz answer my question​

Answer 1

${(2x + 3y)}^{3} = 2x \times 2x \times 2x + 3y \times 3y + 3y \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = {8x}^{3} + {27y}^{3} \\ {(2x - 3y)}^{3} = 2x \times 2x \times 2x - 3y \times 3y \times 3y \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = {8x}^{3} - {27y}^{3} \\ {(x + 2y + 3z)}^{2} = x\times x + 2y \times 2y + 3z \times 3z \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = {x}^{2} + {4y}^{2} + {9z}^{2}$