Question

plz answer my question

Answer 1

Angle AOC = 100° {given}

So, Angle APC = 100°/2 = 50° { 2:1 theorem }

We know that, ABCP is a cyclic quadrilateral

So, Angle APC + Angle ABC = 180°

=> Angle ABC = 130°

Now, Angle ABC + Angle CBD = 180° { linear pair }

Therefore, Angle CBD = 50°

Here, Angle APC = Angle CBD { since, exterior angle property of a cyclic quadrilateral }

So, we can directly write down Angle CBD = 50°

Hope this helps .....