Math, asked by tanishka614, 10 months ago

plz answer my question 4​

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Answered by xevilplaylistx
1

HEYA MATE !

hope it helps

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Answered by Anonymous
5

\mathrm{Given : Total\;Length\;of\;Rope = 15\dfrac{1}{2} = \bigg[15 + \dfrac{1}{2}\bigg]}

\mathrm{\implies Total\;Length\;of\;Rope = \bigg[\dfrac{30 + 1}{2}\bigg] = \dfrac{31}{2}}

\mathrm{Given : Three\;pieces\;of\;lengths\;1\dfrac{2}{5}\;m,\;2\dfrac{2}{3}\;m,\;4\dfrac{5}{9}\;m\;are\;cut\;off}

Total Length of Rope which is cutoff :

\mathrm{\implies 1\dfrac{2}{5} + \;2\dfrac{2}{3} + 4\dfrac{5}{9}}

\mathrm{\implies 1 + \dfrac{2}{5} + 2 + \dfrac{2}{3} + 4 + \dfrac{5}{9}}

\mathrm{\implies 7 + \dfrac{2}{5} + \dfrac{2}{3} + \dfrac{5}{9}}

\mathrm{\implies 7 + \dfrac{9(2) + 15(2) + 5(5)}{45}}

\mathrm{\implies 7 + \dfrac{18 + 30 + 25}{45}}

\mathrm{\implies 7 + \dfrac{73}{45}}

\mathrm{\implies \dfrac{45(7) + 73}{45}}

\mathrm{\implies \dfrac{315 + 73}{45}}

\mathrm{\implies \dfrac{388}{45}}

Length of remaining rope = Actual Length - Cutoff Length

\mathrm{\implies \dfrac{31}{2} - \dfrac{388}{45}}

\mathrm{\implies \dfrac{45(31) - 388(2)}{90}}

\mathrm{\implies \dfrac{1395 - 776}{90}}

\mathrm{\implies \dfrac{619}{90}}

\mathrm{\implies 6.87\;m}

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