Question

Plz answer my question.....

Answer 1

Given that

angle A is bisected by AD

=> angle BAD = angle CAD

Also, AD is perpendicular to BC

=> angle ADB = angle ADC (90° each)

Now we are not given that AB = AC. We have to show it.
We are not even given BD = CD.

We have two angles equal and one side common (AD) in ∆ABD and ∆ACD.

So, we have two criterion

ASA or AAS

Now, side AD lies in between of angle BAD and angle BDA.

Hence, ASA would be used to show congruency.

Answer = ASA (angle-side-angle) congruency would be used.