Plz answer my question.....
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Given that
angle A is bisected by AD
=> angle BAD = angle CAD
Also, AD is perpendicular to BC
=> angle ADB = angle ADC (90° each)
Now we are not given that AB = AC. We have to show it.
We are not even given BD = CD.
We have two angles equal and one side common (AD) in ∆ABD and ∆ACD.
So, we have two criterion
ASA or AAS
Now, side AD lies in between of angle BAD and angle BDA.
Hence, ASA would be used to show congruency.
Answer = ASA (angle-side-angle) congruency would be used.
angle A is bisected by AD
=> angle BAD = angle CAD
Also, AD is perpendicular to BC
=> angle ADB = angle ADC (90° each)
Now we are not given that AB = AC. We have to show it.
We are not even given BD = CD.
We have two angles equal and one side common (AD) in ∆ABD and ∆ACD.
So, we have two criterion
ASA or AAS
Now, side AD lies in between of angle BAD and angle BDA.
Hence, ASA would be used to show congruency.
Answer = ASA (angle-side-angle) congruency would be used.
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