Question

plz answer my question
​as many u can plz but no fake ans

Answer 1

Answer:

i am sending you answers of only two questions because in five points i cant give you answers of all questions but you have to mark it as brainlist.

Answer 2

Answer:

1.

$8 {p}^{3} - 27 {q}^{3} - 36 {p}^{2} q + 54p {q}^{2}$

${(2p)}^{3} - {(3q)}^{3} - 3 \times {(2p)}^{2} \times 3q + 3 \times 2p \times {(3q)}^{2}$

${(2p - 3q)}^{3}$

3.

$4 {x}^{2} + 9 {y}^{2} + 16 {z}^{2} + 12xy - 24yz - 16xz$

${(2x)}^{2} + {(3y)}^{2} + {( - 4z)}^{2} + 2 \times (2x) \times (3y) + 2 \times (3y) \times ( - 4z) + 2 \times (2x) \times ( - 4z)$

${(2x + 3y - 4z)}^{2}$

4.

$a - b - {a}^{3} + {b}^{3}$

$(a - b) - ( {a}^{3} - {b}^{3} )$

$(a - b) - ((a - b)( {a}^{2} + ab + {b}^{2} ))$

$(a - b)(1 - ( {a}^{2} + ab + {b}^{2} ))$

$(a - b)(1 - {a}^{2} - ab - {b}^{2} )$

5.

$(x - 2) \: is \: a \: factor \: of \: the \: polynomial \: {x}^{3} + 10 {x}^{2} + 7x + q$

$so$

${2}^{3} + 10 \times {2}^{2} + 7 \times 2 + q = 0$

$8 + 10 \times 4 + 7 \times 2 + q = 0$

$8 + 40 + 14 + q = 0$

$q + 62 = 0$

$q = - 62$

7.

$3 {x}^{4} - 243$

$3( {x}^{4} - 81)$

$3( { {x}^{2} }^{2} - {9}^{2} )$

$3(( {x}^{2} + 9)( {x}^{2} - 9))$

$3(( {x}^{2} + 9)( {x}^{2} - {3}^{2} ))$

$3(( {x}^{2} + 9)(x + 3)(x - 3))$

$3( {x}^{2} + 9)(x + 3)(x - 3)$

8.

${x}^{3} - 5 {x}^{2} + 4x - 3$

${2}^{3} - 5 \times {2}^{2} + 4 \times 2 - 3$

$8 - 20 + 8 - 3 = - 7$

$the \: remainder \: is \: - 7$

13.

${x}^{2} + 9x + 18$

${x}^{2} + 6x + 3x + 18$

$x(x + 6) + 3(x + 6)$

$(x + 3)(x + 6)$