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- From 0 to 10
- From 10 to 20
- 7.5m
- 7.5m
- 45m/s
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(a) The bus is accelerating in the period of 1-10 minutes.
(b) The bus is decelarating in the period of 11-20 minutes.
(c) The distance covered during the acceleration is area of the triangle = (1/2) × (base)×(height)=1/2 × 10 × 40 =200m.
(d) The distance covered during the deceleration is area of the triangle = (1/2) × (base) × (height) = 1/2 × 10 ×40 = 200m.
(e) Average Speed = Total distance/Total Time
= 1/2 × 20 ×40 =400/20
=400/20 = 20m/s
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