Question

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Answer 1

Solutions:

a)

tan[(3π/2) + θ]

Firstly , converting radians → degrees

3 × π/2 = 3 × 90°. [°.° π/2 = 90°]

Now ,

tan[180° + θ] = tanθ. [answer]

b)

sec(π - θ)

Firstly converting radians to degrees

Already we know that

π = 180°

Now,

sec(π - θ) = sec(180° - θ)

sec(π - θ) = - secθ. [answer]

c)

cos(150°)

It can be written as

cos(90° + 60°)

Using cos(A + B) = cosAcosB - sinAsinB

cos(150°) = cos90°cos60° - sin90°sin60°

cos(150°) = 0(1/2) - 1(√3/2)

cos(150°) = -√3/2. [answer]

d)

sin(225°)

It can be written as

sin(180° + 45°)

Using

sin(180° + θ) = - sinθ

sin(225°) = - sin45°

sin225° = -1/√2. [answer]

Answer 2

Answer:I hope it will help you

Explanation:

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