Question

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Answer 1

Answer:

Step-by-step explanation:

a²-3a+2

=a²-2a-a+2

=a(a-2)-1(a-2)

=(a-1)(a-2)

(a-1)x² + (a²-1)x+(a-1)(a-2)=0

Discriminant = b²-4ac

(a²-1)² - 4(a-1)(a-1)(a-2)

=(a+1)²(a-1)² - 4(a-1)²(a-2)

=(a-1)²[(a+1)²-4(a-2)]

=(a-1)²[a²-2a+1-4a+8]

=(a-1)²(a²-6a+9)

=(a-1)²(a-3)²

√b²-4ac = (a-1)(a-3)

Roots = -b±√b²-4ac/2a

= -(a²-1) ±(a-1)(a-3)/2(a-1)

= -(a+1)(a-1)±(a-1)(a-3)/2(a-1)

= -(a+1)±(a-3)/2

=-(a+1)+(a-3)/2  or -(a+1)-(a-3)/2

= (-a-1+a-3)/2    or (-a-1-a+3)/2

= -4/2   or -2a/2

= -2 or -a