plz answer my question of maths of class ninth. My question is from Dinesh book that is.
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Q2 answer is 180° i think
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ans.2 Suppose the required angle be x.
Then its complement = 90 - x
So ATQ we have;
x=2 (90-x)
x=180-2x
3x=180
x= 60
60°is the answer
ANS.4Let the two angles be x and y.
Since the angles are supplementary.
x+y= 180°
Now according to the question
x-y= 34°
Adding equation 1 and 2 we get,
x=107°
y=73
hope this will help you...
plz mark this as brainliest
Then its complement = 90 - x
So ATQ we have;
x=2 (90-x)
x=180-2x
3x=180
x= 60
60°is the answer
ANS.4Let the two angles be x and y.
Since the angles are supplementary.
x+y= 180°
Now according to the question
x-y= 34°
Adding equation 1 and 2 we get,
x=107°
y=73
hope this will help you...
plz mark this as brainliest
AryanDeo:
welcome
x + x +34 =180
2x = 146
x =73
angle x = 73
angle y = 73 + 34 =107
2x = 146
x =73
angle x = 73
angle y = 73 + 34 =107
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your welcome
please answer my another question
the angle which is 8 times its complement. options are 80° 72° 90°88°
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