Question

plz answer MY question.....solve for x

Answer 1

Given equation

$4x^2 + 10x -90 = 0$

then by using quadratic formula

x = $\frac{ -b ±\sqrt{b^2- 4ac}}{2a}$

x = $\frac{ -10 ±\sqrt{10^2- 4×4×(-90)}}{8}$

x = $\frac{ -10 ±\sqrt{100+144}}{8}$

x = $\frac{ -10 ±\sqrt{244}}{8}$

x = $\frac{ -10 ±2 \sqrt{61}}{8}$

x = $\frac{2\sqrt{61} - 10 }{8}$
= $\frac {\sqrt{61}- 5}{4}$

and x = $\frac{-(2\sqrt{61} + 10) }{8}$
= $\frac {-(\sqrt{61} + 5)}{4}$