Question

plz answer my question solve it ill mark u as brainliest ​

Answer 1

Given,

P = 5000

R = 12%

N = 2years and 5months

To find,

• The compound interest
• The compound amount

Solution,

$amount = p(1 + \frac{r}{100})^{n}$

Let us find for the first 2 years using this formula

Amount = 5000(1 + 12/100)²

= 5000(112/100)² (Cross Multiplication)

= 5000 × 112/100 × 112/100

= 6272

Interest at the end of the second year = A - P

= 6272 - 5000

= 1272

1month = 1/12 year

5months = 5/12 year

The principal for the next two years = 6272

S.I = PRT/100

= 6272×12×5/12×100

= 313.75

Amount = P + I

= 6272 + 313.75

= 6,585.75

Therefore at the end of the 2nd

Year,

Amount= 6585.75

Interest = 1585.75 (1272 + 313.75)

Hope this helps you, please mark this as the brainliest

Answer 2

Answer:

Step-by-step explanation:

Given that,

P = Rs. 5000

r = 12%

Time period = T ( or ) n = 2.5 years = (2 + 5/12) years = 29/12 years.

∴Interest = I = PTR / 100

= 5000 × (29/12) × ( 12 / 100 )

= 50 × 29

= Rs. 1450 is the ananswer