plz answer my questions because it is very urgent
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in fig
∆pbs
tan60=PS/bS
√3=1/BS
BS=1/√3
total length =1+1/√3=BR
∆ABR
cos60=BR/AB
1/2=1+√3/AB
AB=2+2√3
=2+2×1.732=2+3.464
=5.464
∆pbs
tan60=PS/bS
√3=1/BS
BS=1/√3
total length =1+1/√3=BR
∆ABR
cos60=BR/AB
1/2=1+√3/AB
AB=2+2√3
=2+2×1.732=2+3.464
=5.464
chrisi0702:
thanks a lot!! answer more n help me
your welcome
can you help me more in other questions ive posted......????plz!!
yes why not.
thankyou but it was the wrong amswer
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