plz answer my questions
it' s very urgent
promise to Mark as BRAINLIEST
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1. Exterior angle of a equilateral triangle is 120°
2. The sum of angle ROQ and angle ROP is 180° (as it is linear pair angles )
so ,
( 2x + 10 )+ 3x = 180°
5x = 180 - 10
5x = 170
× = 34°
3. QXM = AMX = 135 ( Alternate angles )
so , XMB = 180 - 135 = 45°
yMB = MYR = 40
XMY = YMB + XMB = 40 + 45= 85.
4. I hope you know how to prove !
Well ,
Given that y-30, y - 20 , y - 10 is angles of a triangle . so its sum should be 180
y - 30 + y - 20 + y - 10 = 180
3y -30-20-10 = 180
3y - 60 = 180
3y = 180 - 60
3y = 120
y = 120/3
y = 40
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