Question

plz answer no spam
The ages of sonu and Monu are in the ratio 7 : 5. Ten years hence, the ratio of their ages will be 9 : 7. Find their present ages.​

Answer 1

Step-by-step explanation:

Let the present age of Sonu be 7x years

Present age of Monu be 5x years

Sonu’s age after 10 years = (7x + 10) years

Monu’s age after 10 years = (5x + 10) years

So, (7x + 10) / (5x + 10) = 9/7

by using cross-multiplication we get,

7(7x + 10) = 9(5x + 10) 49x + 70

= 45x + 90 49x – 45x

= 90 – 70 4x

= 20 x

= 20/4 = 5

∴ Present age of Sonu is 7x = 7(5) = 35years

Present age of Monu is 5x = 5(5) = 25years

Answer 2

$\huge{ \underline{ \mathtt{ \red{❥A} \pink{n}\green{S} \blue{W} \purple{E \orange{R}}}}}$

$Let \: the \: present \: age \: be \: 7x \: and \: 5x</p><p>$

After 10 year

$age \: ofsonu = 7x + 10$

$age \: of \: monu \: = 5x + 10$

According to the question

$= > \frac{7x + 10}{5x + 10} = \frac{9}{7}$

$By \: cross \: multiplication$

$= > 7(7x + 10) = 9(5x + 10)$

$= > 49x + 70 = 45 + 90$

$= > 49x - 45x = 90 - 70$

$= > 4x = 20$

$= > x = \frac{20}{4}$

$= > x = 5$

Present age of Sonu = 7x= 7×5= 35years

Present age of Monu = 5x= 5×5= 25years

Mark as brainliest plzzz