Question

plz answer not getting

Answer 1

${3}^{2x + 1} \div 9 = 27 \\ {3}^{2x + 1} \div {3}^{2} = {3}^{3} \\ {3}^{(2x + 1) - 2} = {3}^{3} \\ {3}^{2x -1} = {3}^{3}$
Comparing The Powers ......
$2x - 1 = 3 \\ or2x = 4 \\ x = 2$
So
$x = 2$
is the right answer...
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Answer 2

✨hey mate! here's your answer!✨

since,

$( {3})^{2x + 1 } \div 9 = 27$

$( {3})^{2x + 1} \div ( {3})^{2} = ( {3})^{3}$

$( {3})^{2x + 1 - 2} = ( {3})^{3}$

$2x + 1 - 2= 3$

$2x - 1= 3$

$2x = 3 + 1$

$x = \frac{4}{2}$

$x = 2$

hope it is helpful ✌️!