Question

plz answer of questions 10 and 11....​mark brainliest

Answer 1

Answer:

6.15200 cm^2

Step-by-step explanation:

Question number 11

Area of shaded region = Area of quadrant - Area of triangle AOD

Area of triangle = 1/2 * base * height

= 1/2 * 3.5 * 2

= 3.5 cm^2

Area of quadrant = 90/360* 22/7*3.5*3.5

=9.6250 cm^2

Therefore area of shaded region = 9.6250-3.5

= 6.15200 cm^2

Answer 2

$<b><marquee>☺️HÈLLØ!!☺️</marquee>$

Question 10 :-

• REFER THE ATTACHMENT PLEASE....!!

Question 11 :-

Solution :-

since OACB is a quadrant, it will substend 90° at O.

Area of quadrant OACB

$= \frac{90}{360} \times \pi \times {r}^{2}$

$= \frac{1}{4} \times \frac{22}{7} \times {3.5}^{2}$

$= \frac{77 }{8} {cm}^{2}$

Area of ∆OBD

$= \frac{1}{2} \times ob \times od$

$= \frac{1}{2} \times 3.2 \times 2$

$= \frac{7}{2} {cm}^{2}$

Area of the shaded region

= Area of Quadrant OACB - Area of ∆ OBD

$= \frac{77}{8} - \frac{7}{2}$

$= \frac{49}{8} {cm}^{2}$

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