Question

plz answer..only of u know ..don't want unwanted answers​

Answer 1

Answer:

Required dimension formula of alpha is [ L T$^{-5/2}$ ] .

Correct option is ( 3 ).

Explanation:

From the properties of dimensions :

• For a physical quantity, dimensions of both sides must be equal.

Thus,

= > Dimension of velocity = Dimension of product of $\alpha \: and \: t^{3/2}$

= > [ Velocity ] = [ $\alpha$ ] [ t $^{3/2}$ ]

= > [ L T$^{-1}$ ] = [ $\alpha$ ] [ T ]$^{3/2}$

= > [ L T$^{-1}$ ] / [ T$^{3/2}$ ] = [ $\alpha$ ]

= > [ L T$^{-1-3/2}$ ] = [ $\alpha$ ]

= > [ L T$^{-5/2}$ ] = [ $\alpha$ ]

Hence, the required dimension formula of alpha is [ L T$^{-5/2}$ ] .

Answer 2

Answer:

option 3 is correct

Explanation:

THROUGH THE DIMENSIONS