plz answer ................,,,,,,,,, physics numerical
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Answer:
Force applied = 1 Newton or 1 kg m/s^2
Explanation:
Given,
mass of body = 500g = 500/1000 kg = 5/10 kg
initial velocity= 0m/s
distance travelled = 4m
time taken to travel that distance= 2sec
Force applied =?
From second law of motion
s = ut + 1/2 at^2
4 = 0 x 2 + 1/2 x a x 2 x 2
4 = 0 + 2a
4 = 2a
4/2 = a
a = 2 m/s^2
From Newton's second law of motion
F = ma
F = 5/10 x 2
F = 1/2 x 2
F = 1 Newton or 1 kg m/s^2
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