Question

plz answer plz ????​

Answer 1

Hello, Buddy!!

ɢɪᴠᴇɴ:-

• ∠POR:∠ROQ = 5:7

ᴛᴏ ꜰɪɴᴅ:-

• Value of all angles.

ʀᴇQᴜɪʀᴇᴅ ꜱᴏʟᴜᴛɪᴏɴ:-

Let,

∠POR = 5x

∠ROQ = 7x

→ ∠POR+∠ROQ = 180° [Linear Angles]

→ 5x+7x = 180°

→ 12x = 180°

→ x = 180°/12

→ x = 15°

∠POR = 5x => 5×15° → 75°

∠ROQ = 7x => 7×15° → 105°

∠POR = ∠POS [Vertically Opposite Angles]

∠ROQ = ∠SOQ [Vertically Opposite Angles]

• ∠POR = 75°
• ∠ROQ = 105°
• ∠POS = 75°
• ∠SOQ = 105°

$\boxed{\tt{@MrMonarque♡}}$

Hope It Helps You ✌️

Answer 2

GIVEN :-

$\sf \blue{ \angle POR : \angle ROQ = 5:7}$

TO FIND :-

Value of all the angles.

SOLUTION :-

Let,

$\sf \angle POR = 5x$

$\sf \angle ROQ = 7x$

Now,

$\sf → \angle POR+ \angle ROQ = 180 \degree$

[Linear Angles]

$\sf → 5x+7x = 180 \degree$

$\sf → 12x = 180 \degree$

$\sf → x = \frac{180 \degree}{12}$

$\sf \fbox{→ x = 15 \degree}$

Now,

$\sf \green{ \angle POR = 5x = 5×15 \degree = 75 \degree}$

$\sf \green{ \angle ROQ = 7x = 7×15 \degree = 105 \degree}$ [Vertically Opposite Angles]

$\sf \green{\angle ROQ = \angle SOQ}$ [Vertically Opposite Angles]

Hence, the value of the angles are :-

$\sf \red{ \angle POR =75 \degree}$

$\sf \red{ \angle ROQ = 105 \degree}$

$\sf \red{\angle POS = 75 \degree}$

$\sf \red{\angle SOQ = 105 \degree}$