Question

Plz answer plz i will mark brainlist answrr​

Answer 1

$\huge\star\bold\red{ANSWER}$

proof:-Since, a³+b³+c³−3abc=(a+b+c)(a²+b²+c² −bc−ca−ab)

Given, a+b+c=0

∴a³+b³+c³−3abc=0

∴a³+b³+c³=3abc

ANSWER=>3(abc)

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