Question

plz answer plz its urgent

Answer 1

here is ur answer
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Answer 2

$x + \frac{1}{x} = 2.5 \\ \frac{ {x}^{2} + 1}{x} = 2.5 \\ {x}^{2} + 1 = 2.5x \\ {x}^{2} - 2.5x + 1 = 0 \\ a = 1 \: \: \: \: b = 2.5 \: \: \: \: c = 1 \\ \frac{ - b + - \sqrt{ {b}^{2} - 4ac } }{2a} \\ \frac{ - 2.5 + - \sqrt{ {2.5}^{2} - 4 \times 1 \times 1} }{2 \times 1} \\ \frac{ - 2.5 + - \sqrt{6.25 - 4} }{2} \\ \frac{ - 2.5 + - \sqrt{10.25} }{2} \\ \frac{ - 2.5 + -( 3.2)}{2} \\ taking \: + \\ \frac{ - 2.5 + 3.2}{2} \\ \frac{0.7}{2} \\ x = 0.35 \\ \\ taking \: - \\ \frac{ - 2.5 - 3.2}{2} \\ \frac{5.7}{2} \\ x = 2.85$
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