Question

Plz answer plz plz plz plz plz​

Answer 1

$\huge\mathcal{\fcolorbox{cyan}{black}{\pink{ANSWER}}}$

$\displaystyle \int _ \frac{ - \pi}{2} ^0 \: \: sin \: x \: \: dx + \int _ 0 ^ \frac{ \pi}{2} \: \: sin \: x \: \: dx \: \\ = [ - cos \: x ]_ \frac{ - \pi}{2} ^0 \: \: + \: \: [ - cos \: x]_ 0 ^ \frac{\pi}{2} \\ = [ - cos \: (- \frac{\pi}{2} )\: \: - \: cos \: 0] + ( - cos \: 0 - \: cos \: \frac{\pi}{2} ) \\ = (0 - 1) + ( - 1 - 0) \\ = - 1 - 1 \\ = - 2$