Math, asked by mili1978piku2, 1 year ago

plz answer Q-10, if you then only u answer otherwise plz don't spam or ask anything else....

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Answered by Yuichiro13
1
Ah !

Your Question Simplifies to :

 {4}^{5 log_{ {2}^{ \frac{5}{2} } }(3 -  \sqrt{6} )  - 6 log_{ {2}^{3} }( \sqrt{3 }  -  \sqrt{2} )  }

Which hopefully reduces to :

 {4}^{ \frac{2}{5} .5 log_{2}(3 -  \sqrt{6} ) +  \frac{6}{3}  log_{2}( \sqrt{3} -  \sqrt{2}  )  }

Which further reduces to :

 {4}^{2log_{2}( \frac{3 -  \sqrt{6} }{ \sqrt{3}  -  \sqrt{2} } ) }
 =  {( \frac{3 -  \sqrt{6} }{ \sqrt{3}  -  \sqrt{2} } )}^{2 log_{2}(4) }

 =   { \sqrt{3}  }^{ \: 4}  = 9

mili1978piku2: thank you
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