Physics, asked by falgunichapekar, 1 year ago

Plz answer Q. 8, 9 it's urgent

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Answered by poojan
9
9.
         V = L¹T⁻¹
         F = M¹L¹T⁻²
         T = T¹

(A). We know that, Force = Mass x Acceleration = M x V/T ⇒ M = F x T/V

       M = (M¹L¹T⁻²)(T¹)(L⁻¹T¹) = M¹L°T°

Therefore, Dimensional formula of Mass under given condition is M¹L°T°.



(B) Energy = Workdone / time = Force x distance/time = F x V x T/T = Fx V

      Energy = V x F
                  = ( L¹T⁻¹)( M¹L¹T⁻²)
                  = M¹L²T⁻³

Therefore, Dimensional formula of Energy under given condition is M¹L²T⁻³.


                                          =============


8. Dimensional formulas of
    C or V = M⁰L¹T⁻¹
    G        = M⁻¹L³T⁻²
    H        = M¹L²T⁻¹

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Thank you!


    
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