Question

Plz Answer q 9 ,10 about congruent triangles​

Answer 1

Answer:

Q. No. 9.:-

In ∆PQS & ∆RQS

PS = RS (Given)

PQ = TQ (Given)

QS = QS (Common)

HENCE :- By SSS

∆PQS Cong. ∆PQS

Q. No. 10:-

In ∆PSQ & ∆PSR

< QPS = < RPS (PS is the bisector of < P)

< PSQ = < PSR (Each 90°)

PS = PS (Common)

HENCE :- By AAS

∆PSQ Cong. ∆PSR

Answer 2

Step-by-step explanation:

Q9 .in triangle PQS and RQS , PS =RS (given) ,PQ=RQ(given ), SQ=SQ (common side ) hence ∆PQS and RQS are congruent by SSS congruency . Q10 . in ∆PSQ and PSR QPS=RPS (PS is the bisector of P) , PSQ=PSR each 90°(PS perpendicular on QR ) , PQ=PR( side opposite to equal angle are equal) by AAS congruency PSQ congruent PSR