Question

plz answer Q1 (iv).........​

Answer 1

i hope it will be helpful to you

Answer 2

Step-by-step explanation:

Let p(x)=x³-x²-(2+√2)x+√2

The zero of x+1=-1

p(-1)=(-1)³-(-1)²-(2+√2)x+√2

=-1-1+2+√2+√2

=2√2